# TCS Question Bank Quants 15

Find solutions for all the questions at the end of each set:

### Set A

1. When 335 added to 5A7,the result is 8B2.8B2 is divisible by 3.What is the largest posible value of A ?
(1). 8
(2). 2
(3). 1
(4). 4
2. The greatest 4-digit number exactly divisible by 10,15,20 is
(1). 9990
(2). 9960
(3). 9980
(4). 9995
3. Which one of the numbers is divisible by 25?
(1). 303310
(2). 373355
(3). 303375
(4). 22040
4. In a class there are ‘z’ students. out of them ‘x’ are boys.what part of the class is composed of girls?
(1). x/z
(2). z/x
(3). 1-x/z
(4). x/z-1
5. If the students of 9th class are arranged in row of 6,8,12 or 16,no students left behind .Then the possible number of students in the class is
(1). 60
(2). 72
(3). 80
94). 96
6. The unit digit in 3*38*537*1256 is
(1). 4
(2). 2
(3). 6
(4). 8
7. If a clock strikes appropriate number of times at each hour ,how many times will it strike  a days ?
(1). 300
(2). 156
(3). 68
(4). 78
8. A farmer can plough a field working 6 hours per day in 18 days. The worker has to work how many hours per day to finish the same work in 12 days ?
(1). 7
(2). 9
(3). 11
(4). 13
9. The third proportional of 12 and 18 is
(1). 3
(2). 6
(3). 27
(4). 144
10. If Rs.126.5 is divided among A,B,and C in the Ratio of 2:5:4 ,the share of B exceeds that of A by
(1). Rs.36.50
(2). Rs.35.50
(3). Rs.34.50
(3). Rs.33.50
Answers and Solution:
1.(4)
2.(2)
LCM of 10 ,15 and 20 = 60
Largest 4-digit number = 9999
So required number = 9999-39 = 9960
3.(3)
4.(3)
Boys = x
Girls = z-x
so parts of girls = z-x/z = 1-x/z
5.(4)
6.(4)
Unit’s digit in 3*38*537*1256
= unit digit in 3*8*7*6
= 4*2 = 8
7.(2)
8.(2)
D1T1 = D2T2
=> 18*6 = 12*T2
=> T2 = 9 hours
9.(3)
10.(3)
A:B:C = 2:5:4
sum of ratios = 2+5+4 = 11
Difference = (5/11 – 2/11)*126.50
=  Rs.34.50
Find solutions for all the questions at the end of each set:

### Set B

1. When 335 added to 5A7,the result is 8B2.8B2 is divisible by 3.What is the largest posible value of A ?
(1). 8
(2). 2
(3). 1
(4). 4
2. The greatest 4-digit number exactly divisible by 10,15,20 is
(1). 9990
(2). 9960
(3). 9980
(4). 9995
3. Which one of the numbers is divisible by 25?
(1). 303310
(2). 373355
(3). 303375
(4). 22040
4. In a class there are ‘z’ students. out of them ‘x’ are boys.what part of the class is composed of girls?
(1). x/z
(2). z/x
(3). 1-x/z
(4). x/z-1
5. If the students of 9th class are arranged in row of 6,8,12 or 16,no students left behind .Then the possible number of students in the class is
(1). 60
(2). 72
(3). 80
94). 96
6. The unit digit in 3*38*537*1256 is
(1). 4
(2). 2
(3). 6
(4). 8
7. If a clock strikes appropriate number of times at each hour ,how many times will it strike  a days ?
(1). 300
(2). 156
(3). 68
(4). 78
8. A farmer can plough a field working 6 hours per day in 18 days. The worker has to work how many hours per day to finish the same work in 12 days ?
(1). 7
(2). 9
(3). 11
(4). 13
9. The third proportional of 12 and 18 is
(1). 3
(2). 6
(3). 27
(4). 144
10. If Rs.126.5 is divided among A,B,and C in the Ratio of 2:5:4 ,the share of B exceeds that of A by
(1). Rs.36.50
(2). Rs.35.50
(3). Rs.34.50
(3). Rs.33.50
Answers and Solution:
1.(4)
2.(2)
LCM of 10 ,15 and 20 = 60
Largest 4-digit number = 9999
So required number = 9999-39 = 9960
3.(3)
4.(3)
Boys = x
Girls = z-x
so parts of girls = z-x/z = 1-x/z
5.(4)
6.(4)
Unit’s digit in 3*38*537*1256
= unit digit in 3*8*7*6
= 4*2 = 8
7.(2)
8.(2)
D1T1 = D2T2
=> 18*6 = 12*T2
=> T2 = 9 hours
9.(3)
10.(3)
A:B:C = 2:5:4
sum of ratios = 2+5+4 = 11
Difference = (5/11 – 2/11)*126.50
=  Rs.34.50