Cryptarithmetic Problem – 1

Ques. For the following Cryptarithmetic find the answers to the below questions?

       J  E
       B  B
       ----
       J  E
    J  E  A
   --------
 B  A  D  E

Assume that E = 4

cheap tadalafil 20mg 1. is it safe to buy viagra online yahoo answers Value of 5B?
(a) 15 (b) 10 (c) 5
2. Value of B + A?
(a) 7 (b) 5 (c) 1 (d) 8
3. Value of  D ?
(a) 4 (b) 3 (c) 7 (d) 8

Clearly, from second row where 
x is written in common multiplication 
that value is not considered so ideally 
here we will hav the value A = 0.

It is very obvious that the value of B is 1 For e.g.
Since, for Row 3 JE x B give JE itself thus B=1. J E 1 1 —– -> J E (Row 3) J E 0 <-———-
B A D E

       J  E
       1  1
       ----
       J  E
    J  E  0
   --------
 1  0  D  E
Now in the hundred's place, J + value = 10. Also, J is non zero since A = 0. Thus J should be
9. When you add something to the single digit number that results in 10. So J = 9. 

Now, problem looks like-

       9  E
       1  1
       ----
       9  E
    9  E  0
   --------
 1  0  D  E
Unfortunately we can't predict the values of values of E and D, but we can obviously deduce that
, that E and D are consecutive and D = 9 + 1(carry over) + E. Thus D = E + 1 and E = 0 + E 
As it is given that E = 4, we can say D = 3.