# Cryptarithmetic Problem – 1

Ques. For the following Cryptarithmetic find the answers to the below questions?

```       J  E
B  B
----
J  E
J  E  A
--------
B  A  D  E

Assume that E = 4

```
 cheap tadalafil 20mg 1. is it safe to buy viagra online yahoo answers Value of 5B? (a) 15 (b) 10 (c) 5
 2. Value of B + A? (a) 7 (b) 5 (c) 1 (d) 8
 3. Value of  D ? (a) 4 (b) 3 (c) 7 (d) 8
```
Clearly, from second row where
x is written in common multiplication
that value is not considered so ideally
here we will hav the value A = 0.```

It is very obvious that the value of B is 1 For e.g.
Since, for Row 3 JE x B give JE itself thus B=1. J E 1 1 —– -> J E (Row 3) J E 0 <-———-
B A D E

```       J  E
1  1
----
J  E
J  E  0
--------
1  0  D  E```
```Now in the hundred's place, J + value = 10. Also, J is non zero since A = 0. Thus J should be
9. When you add something to the single digit number that results in 10. So J = 9.

Now, problem looks like-

```
```       9  E
1  1
----
9  E
9  E  0
--------
1  0  D  E```
```Unfortunately we can't predict the values of values of E and D, but we can obviously deduce that
, that E and D are consecutive and D = 9 + 1(carry over) + E. Thus D = E + 1 and E = 0 + E
As it is given that E = 4, we can say D = 3.```