Questions with 90% Probability of coming in every eLitmus exam All Repeated Questions(Repeated At least 10 times each)

• eLitmus Cryptarithmetic Previous Questions from all Years – Paid

• Cryptarithmetic Previous Question – 1
• Cryptarithmetic Previous Question – 2
• Cryptarithmetic Previous Question – 3

                       W  B  A
                    x  B  P  W
                    C  X  R  F
                 F  X  A  X
              A  A  C  C      
              A  P  C  A  B  F
Firstly divide the problem in three parts. As,
 

(1)      W  B  A             (2)     W  B  A        (3)      W  B  A
            x  W                        x  P                    x  B
      C  X  R  F                  F  X  A  X              A  A  C  C
 
Now, you have to select one from three which has maximum number of clues.i.e. maximum number of variables getting repeated.
In this case take,
(3)          W  B  A
                x  B 
          A  A  C  C
Now, you have to start hit and trial with the possible values C i.e.
 
C={1, 2, 3, 4, 5, 6, 7, 8, 9} 
  
Firstly take  C=1 and check further

Possible ways of getting 1 as Unit Digit

(3)                                  W  B  A 
                                        x  B
                                  A  A  C  C 

then
Case 1     C=1  A=1  B=1   Rejected As A = B = C [violates the Basic Cryptarithmetic Rules.]
Case 2     C=1  A=7  B=3   Needs to be checked further
Case 3     C=1  A=3  B=7   Needs to be checked further
Case 4     C=1  A=9  B=9   Rejected As A = B  [violates the basic Cryptarithmetic Rules.]
Now check for Case 2 and Case 3 only.
(3)     W  B  A
            x B
     A  A  C  C 

        W  3  7
           x  3
     7  7  1  1
Rejected as,  even after taking the value of W=9, You will never get 77.
        W  3  7
           x  3
     7  7  1  1
Now, you have to check with case 3
C=1, A=3, B=7
       W  B  A
          x  B
    A  A  C  C

       W  7  3
          x  7
    3  3  1  1 
Here you can easily predict the value of W=4
Hence W=4, C=1, A=3, B=7 put these values in main problem
              4  7  3
           x  7  P  4
           1  X  R  F
        F  X  3  X
     3  3  1  1         
     3  P  1  3  7  F
Now, you can see
              4  7  3
                 x  4
           1  8  9  2 [ 1  X  R  F]
If you compare side by side you will get X=8, R=9 and F=2
Put these values in main problem, and rewrite again
              4  7  3
           x  7  P  4
           1  8  9  2
        2  8  3  8
     3  3  1  1        
     3  P  1  3  7  2
Now, you can easily predict the value of P=6
Hence,
              4  7  3
           x  7  6  4
           1  8  9  2
        2  8  3  8
     3  3  1  1      
     3  6  1  3  7  2
[Relax - it's going to take some time to understand the whole concept. If you are facing any difficulty. Please go through the Cryptarithmetic Tutorial.]

Set 1

Find Solutions at the end of every section

Each question is followed by two statements. You have to decide whether the information provided in the statements is sufficient for answering the question.
Mark A
If the question can be answered by using one of the statements alone, but cannot be answered by using the other statements alone.
Mark B
If the question can be answered by using either statement alone.
Mark C
If the question can be answered by using both statements together, but cannot be answered by using the either statement alone.
Mark D
If the question cannot be answered even by using both the statements together.

Question 1: Who among P, Q, T, V and M is exactly in the middle when they are arranged in ascending order of their heights?
Statements:

V is taller than Q but shorter than M.
T is taller than Q and M but shorter than P.
A. I alone is sufficient while II alone is not sufficient
B. II alone is sufficient while I alone is not sufficient
C. Either I or II is sufficient
D. Neither I nor II is sufficient
E. Both I and II are sufficient

From I, we have: M > V > Q.From II, we have: T > Q, T > M, P > T.Combining the above two, we have: P>T>M>V>Q i.e. Q<v<m<t<p.< p=””>Clearly, M is in the middle.

2.
What is the value of |x|?
Statement.(1)
x = -|x| .
Statement.(2)
x2 = 4.
(a) A
(b) B
(c) C
(d) D

Expl. of Statement (1)

The absolute value of x, |x|, is always positive or 0, so this only determines that x is negative or 0; NOT SUFFICIENT.
Expl. of Statement (2)

Exactly two values of x (x= ±2) are possible, each of which gives the value 2 for |x| SUFFICIENT.
 Answer
(A)  [Each statement alone is not sufficient.]

Question: Which code word stands for ‘good’ in the coded sentence ‘sin co bye’ which means ‘He is good?
Statements:

In the same code language, ‘co mot det’ means ‘They are good’.
In the same code language, ‘sin mic bye’ means ‘He is honest’.
A. I alone is sufficient while II alone is not sufficient
B. II alone is sufficient while I alone is not sufficient
C. Either I or II is sufficient
D. Neither I nor II is sufficient
E. Both I and II are sufficient

Explanation: In the given statement and I, the common word is ‘good’ and the common code word is ‘co’. So, ‘co’ is the code for ‘good’.In the given statement and II, the common words are ‘He’ and ‘is’ and the common code words are ‘sin’ and ‘bye’. So ‘sin’ and ‘bye’ are the codes for ‘He’ and ‘is’. Thus, in the given statement, ‘co’ is the code for ‘good’.

4.
If x is negative, is x < – 3 ?
Statement. (1)
x2  > 9.
Statement. (2)
x3 < -9.
(a) A
(b) B
(c) C
(d) D

Expl. of Statement (1)

Given that  x2> 9, it follows that x < -3 or x > 3, a result that can be obtained in a variety of ways. For example, consider the equivalent equation (|x|) >9 that reduces to |x| >3,or consider when the two factors of x2 —9 are both positive and when the two factors of x2 —9 are both negative, or consider where the graph of the parabola y = x2 – 9 is above the x-axis, etc. Since it is also given that x is negative, it follows that
x< -3; SUFFICIENT.
Expl. of Statement (2)

Given that x3 < -9, if x = -4, then x3  = -64, and so x3 <-9 and it is true that  x < -3. However, if x = —3, then x = —27, and so x3  < —9, but it is not true that x < —3; NOT SUFFICIENT.
 Answer
(A)  [Each statement alone is not sufficient.]

5.
If x and y are integers, is xy even?
Statement. (1)
x = y + l
Statement. (2)
x/y is an even integer..
(a) A
(b) B
(c) C
(d) D

Expl. of Statement  (1)

Determine if xy is even; Since x and y are consecutive integers, one of these two numbers is even, and hence their product is even. For example, if x is even, then x = 2m for some integer m, and thus xy =(2m)y =(my)(2), which is an integer multiple of 2, so xy is even; SUFFICIENT.
Expl. of Statement  (2)

If x /y is even, then x/y= 2n for some integer n, and thus x = 2ny. From this it follows that xy =(2ny)(y) =(ny2)(2), which is an integer multiple of 2, so xy is even; SUFFICIENT.
 Answer
(B)  [Each statement alone is  sufficient.]

6.
Paula and Sandy were among those people who sold raffle tickets to raise money for Club X. If Paula and Sandy sold a total of 100 of the tickets, how many of the tickets did Paula sell?
Statement. (1)
Sandy sold 2/3 as many of the raffle tickets as Paula did
Statement. (2)
Sandy sold 8 percent of all the raffle tickets sold for Club X..
(a) A
(b) B
(c) C
(d) D

Expl. of Statement  (1)

If Paula sold p tickets and Sandy sold s tickets, then p + s = 100. Since Sandy sold 2/3 as many tickets as Paula, s= (2/3)p. The value of p can be determined by solving the two equations simultaneously; SUFFICIENT.
Expl. of Statement  (2)

Since the total number of the raffle tickets sold is unknown, the number of tickets that Sandy or Paula sold cannot be determined NOT SUFFICIENT.
 Answer
(A)  [Each statement alone is not  sufficient.]

7.
What is the number of cans that can be packed in a certain carton?
Statement. (1)
The interior volume of this carton is 2,304 cubic inches
Statement. (2)
The exterior of each can is 6 inches high and has a diameter of 4 inches
(a) A
(b) B
(c) C
(d) D

Expl. of Statement  (1)

No information about the size of the cans is given; NOT SUFFICIENT.
Expl. of Statement  (2)

No information about the size of the carton is given; NOT SUFFICIENT.
 Taking (1) + (2) Together
Taking (1) and (2) together, there is still not enough information to answer the question. If the carton is a rectangular solid that is 1 inch by 1 inch by 2,304 inches and the cans are cylindrical with the given dimensions, then 0 cans can be packed into the carton. However, if the carton is a rectangular solid that is 16 inches by 12 inches by 12 inches and the cans are cylindrical with the given dimensions, then 1 or more cans can be packed into the carton.
 Answer
(D)  [Each statement alone and together is not sufficient.]

Set 2

Find Solutions at the end of every section

Each question is followed by two statements. You have to decide whether the information provided in the statements is sufficient for answering the question.
Mark A
If the question can be answered by using one of the statements alone, but cannot be answered by using the other statements alone.
Mark B
If the question can be answered by using either statement alone.
Mark C
If the question can be answered by using both statements together, but cannot be answered by using the either statement alone.
Mark D
If the question cannot be answered even by using both the statements together.

1.
If n is an integer, is n even ?
Statement.(1)
n^2 -1 is an odd integer.
Statement.(2)
3n + 4 is an even integer.
(a) A
(b) B
(c) C
(d) D

Expl. of Statement (1)
Since n2 —1 is odd, n2 is even and so n is even; SUFFICIENT.

Expl. of Statement (2)

Since 3n+ 4 is even, 3n is even and so n is even; SUFFICIENT.
 Answer
(B)  [Each statement alone is sufficient.]

2.
If n is an integer, is n+ 1 odd ?
Statement. (1)
n+ 2 is an even integer.
Statement. (2)
n-1 is an odd integer.
(a) A
(b) B
(c) C
(d) D
Expl. of Statement (1)

Since n+ 2 is even, n is an even integer, and therefore n+1 would be an odd integer; SUFFICIENT.
Expl. of Statement (2)

Since n-1 is an odd integer, n is an even integer. Therefore n+ 1 would be an odd integer; SUFFICIENT.
 Answer
(B)  [Each statement alone is sufficient.]

3.
Is x a negative number?
Statement. (1)
9x > 10x.
Statement. (2)
x + 3 is positive.
(a) A
(b) B
(c) C
(d) D
Expl. of Statement  (1)

Subtracting 9x from both sides of 9x  > lOx gives 0 > x, which expresses the condition that x is negative; SUFFICIENT.
Expl. of Statement  (2)

Subtracting 3 from both sides of x+ 3 > 0 gives x > -3, and x > -3 is true for some negative numbers (such as -2 and -1) and for some numbers that aren’t negative (such as 0 and 1); NOT SUFFICIENT.
 Answer
(A)  [Each statement alone is  not sufficient.]

4.
What is the tens digit of positive integer x?
Statement. (1)
x divided by 100 has a remainder of 30.
Statement. (2)
x divided by 110 has a remainder of 30.
(a) A
(b) B
(c) C
(d) D

Expl. of Statement  (1)

Having a remainder of 30 when x is divided by 100 can only happen if x has a tens digit of  3 and a ones digit of 0, as in 130, 230, 630, and so forth; SUFFICIENT.
Expl. of Statement  (2)

When 140 is divided by 110, the quotient is 1 R 30. However, 250 divided by 110 yields a quotient of 2 R 30, and 360 divided by 110 gives a quotient of 3 R 30. Since there is no consistency in the tens digit, more information is needed; NOT SUFFICIENT.
 Answer
(A)  [Each statement alone is not  sufficient.]

5.
If k is an integer such that 56 < k < 66, what is the value of k?
Statement. (1)
If k were divided by 2, the remainder would be 1.
Statement. (2)
If k + 1 were divided by 3, the remainder would be O.
(a) A
(b) B
(c) C
(d) D

Expl. of Statement  (1)

Determine the value of the integer k, where 56<k< 66 It is given that the remainder is 1 when k is divided by 2, which implies that k is odd Therefore, the value of k can be 57, 59, 61,63, or 65; NOT SUFFICIENT.
Expl. of Statement  (2)

It is given that the remainder is 0 when k + 1 is divided by 3, which implies that k + 1 is divisible by 3. Since 56 <k <66 (equivalently, 57 <k+1 <67), the value of k + 1 can be 60, 63, or 66 so the value of k can be 59, 62 or 65; NOT SUFFICIENT.
 Taking (1) + (2) Together

Taking (1) and (2) together, 59 and 65 appear in both lists of possible values for k; NOT sufficient.
 Answer
(D)  [Each statement alone and together is not sufficient.]

Set 1

Find Solutions at the end of every section

Set 2

Find Solutions at the end of every section

Set 1

Find Solutions at the end of every section

Set 1

Find Solutions at the end of every section

Each question is followed by two statements. You have to decide whether the information provided in the statements is sufficient for answering the question.
Mark A
If the question can be answered by using one of the statements alone, but cannot be answered by using the other statements alone.
Mark B
If the question can be answered by using either statement alone.
Mark C
If the question can be answered by using both statements together, but cannot be answered by using the either statement alone.
Mark D
If the question cannot be answered even by using both the statements together.

1.If m is an integer, is m odd ?
(I) m/2 is not an even number .
(II) m – 3 is an even integer.
(a) A
(b) B
(c) C
(d) D

2.Total amount of Rs 38500 was distributed among Praveen, Ranjan and Nitesh. How much does each get ?
(I)   Praveen gets 2/9 of what other two get.
(II)  Ranjan gets 3/11 of what other two get.
(a) A
(b) B
(c) C
(d) D

3.Of the 300 students who speak French,Russian or both, how many speak only French ?
(I)  196 students speak both French and Russian.
(II) 58 students speak Russian only.
(a) A
(b) B
(c) C
(d) D

4.If the teacher adds four students to the class,can he evenly distribute the class in groups of 4 students ?
(I) If 12 students are added to the class,then the teacher can divide students evenly in groups of 8.
(II) Initially, the number of students is not divisible by 8.
(a) A
(b) B
(c) C
(d) D

5.Is average (arithmetic mean) score of GMAT 500 ?
(I)  Half of the students scored more than 500 and half less than 500.
(II) Highest is 800 and lowest is 200.
(a) A
(b) B
(c) C
(d) D

6.Is x = y ?
(I)  (x + y) (1/x + 1/y) = 4
(II) (x – 50)(x – 50)=(y – 50)(y – 50)
(a) A
(b) B
(c) C
(d) D

7.Is |x – 2| < 1 ?
(I) |x| < 1
(II)|x-1| < 2
(a) A
(b) B
(c) C
(d) D

8.Two Friends,Ram and Gopal, bought apples from a wholesale dealer. How many apples did they buy ?
(I)   Ram bought one-half the number of apples that Gopal bought.
(II) The wholesale dealer had a stock of 500 apples.
(a) A
(b) B
(c) C
(d) D

9.What is the value of X ?
(I)  X and Y are unequal even integers,less than 10 and X/Y is an odd integer.
(II) X and Y are even integers,each less than 10 and product of X and Y is 12.
(a) A
(b) B
(c) C
(d) D

10What are the values of m and n ?
(I)  n is an even integer m is an odd integer and m is greater than n.
(II) Product of m and n is 30.
(a) A
(b) B
(c) C
(d) D
Answer
1.A
2.C
3.C
4.A
5.D
6.A
7.A
8.D
9.D
10.C

Set 2

Set 1

Find Solutions at the end of every section




Six cricketers from six different nations stay in a five star hotel in different rooms. Each of them eats a different variety of food in a meal and hits different number of sixes in an average match. Now read the following clues carefully.
●  The player in room No. 142 eats twice as much as the number of varieties eaten by player, who hits an average of 8 sixes per match, in a meal.●  The player from New Zealand and the player in room no. 146 eat a combined 40 varieties in a meal.●  The player from India eats 8 varieties less than the player from England but hits 10 more sixes in an average match.
●  Four times the number of varieties in a meal eaten by the player in room No. 144 is lesser than the number of sixes hit by him in an average match.
●  The player in room no. 143 eats 12 varieties per meal and hits 8 sixes on an average in each match.
●  The player who eats 16 varieties per meal hits 24 sixes per match on an average.
●  The player in room No. 145 eats 8 varieties per meal and hits 2 sixes less than the player from the Pakistan on an average in a match.
● The Australian player is staying one rooms after the English who is staying one rooms after the

Pakistani player.
1.In which room is the Australian player staying ?
(a)Room No. 142
(b)Room No. 143
(c)Room No. 144
(d)Room No. 145

2.
What is the average number of sixes hit by the Indian player ?
(a)8
(b)16
(c)18
(d)24

3.How many varieties of food is eaten by English player in his meal ?
(a)8
(b)12
(c)16
(d)20

4.
The player of which country is staying in room No. 146 ?
(a)India
(b)Pakistan
(c)Sri Lanka
(d)England

5.The player of which country hits 24 sixes on an average ?
(a)India
(b)New Zealand
(c)Pakistan
(d)Sri Lanka

1.(D)   2.(C)    3.(B)    4.(C)   5.(D)

Set 2

Find Solutions at the end of every section


Mr. Bankatlal acted as a judge for the beauty contest. There were four participants, viz Ms. Andhra Pradesh, Ms. Uttar Pradesh, Ms. West Bengal and Ms. Maharastra. Mrs. Bankatlal, who was very anxious about the result asked him about it as soon as he was back home. Mr. Bankatlal just told that the one who was wearing the yellow saree won the contest. When Mrs. Bankatlal pressed for further details, he elaborated as follows.●  All of them were sitting in a row.
●  All of them wore sares of different colors, viz. green, yellow, white, red.
●  There was only one runner-up and she was sitting beside Ms. Maharastra.
●  The runner-up was wearing the green saree.
●  Ms. West Bengal was not sitting at the ends and was not the runner up.
●  The winner and the runner-up are not sitting adjacent to each other.
●  Ms. Maharastra was wearing the white saree.
●  Ms. Andhra Pradesh was not wearing green saree.
●  Participants wearing yellow saree and white saree were at the ends.

1.Who wore the red saree ?
(a)Ms. Andhra Pradesh
(b)Ms. West Bengal
(c)Ms. Utter Pradesh
(d)Ms. Maharastra

2.Ms. West Bengal was sitting adjacent to
(a)Ms. Andhra Pradesh and Mr. Maharastra
(b)Ms. Utter Pradesh and Ms. Maharastra
(c)Ms. Andhra Pradesh and Ms. Uttar Pradesh
(d)Ms. Uttar Pradesh Only

3.Which saree was worn by  Ms. Andhra Pradesh ?
(a)Yellow
(b)Red
(c)Green
(d)White

4.Who was the runner-up ?
(a)Ms. Andhra Pradesh
(b)Ms. West Bengal
(c)Ms. Uttar Pradesh
(d)Ms. Maharastra

1.(B)   2.(C)    3.(A)    4.(C)